Customers of the key refining company charge an average of $70 per month. the distribution of amounts charged is approximately normal, with a standard deviation of $10. what is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83

0.4032 is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $70

Standard Deviation, σ = $10

We are given that the distribution of amounts charged is a bell shaped distribution that is a normal distribution.

Formula:

P(customer charged between $70 and $83)

Thus, 0.4032 is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83.

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above