Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. which statement is true? a) only x = –7 is an extraneous solution.
b) only x = 1 is an extraneous solution.
c) both solutions are extraneous.
d)neither solution is extraneous.

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

we know that

two possible solutions are x=-7 and x=1

Verify each solution

Substitute each value of x in the expression above and interpret the results

1) For x=-7

----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

dude thats to long figure it

step-by-step explanation: