Determine the type and number of solutions of x^2 + 2x + 3 = 0.
one real solution
two imaginary solutions
two real solutions

The equation has 2 imaginary solutions

Step-by-step explanation:

x² + 2x + 3 = 0

D = b² - 4ac

= 2² - 4(1)(3)

= -8

< 0

D>0 (2 real solutions)

D=0 (1 real solution)

D<0 (2 imaginary or no real

solutions)

(Correct me if i am wrong)

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

answer

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step-by-step explanation: