Use pascal's triangle to expand the binomial.
(s+3v)^5

a. s^5 - 5s^4 + 10s^3v^2+5sv^4 - v^5
b. s^5 + 15s^4v +90s^3v^2 + 270s^2v^3 + 405sv^4 + 243v^5
c. s^5 + 45s^4v+270s^3v^2+810s^2v^3+1,215sv^ 4 + 729v^5
d. s^5 + 15s^4 + 90s^3 + 270s^2 + 405s + 243

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

you are uyytr tyy

step-by-step explanation: