How do i divide a 6 and 3/4 inch line into three parts so that each part is 1/4 inch shorter than the others before it

  2 1/2, 2 1/4, 2

Step-by-step explanation:

Let x represent the first part. Then the next part is (x -1/4), one-quarter inch shorter. The part after that is ((x -1/4) -1/4), one-quarter inch shorter still.

The sum of these three parts is 6 3/4:

  x + (x -1/4) + (x -1/2) = 6 3/4

  3x -3/4 = 6 3/4 . . . . . . . . . . . . collect terms

  x -1/4 = 2 1/4 . . . . . . . . . . . . . . divide by 3

  x = 2 1/2 . . . . . . . . . . . . . . . . . add 1/4

So, the first piece is 2 1/2; the next piece is 1/4 shorter, so is 2 1/4; and the last piece is 1/4 shorter still, so is 2 inches.

The pieces are 2 1/2 inches, 2 1/4 inches, and 2 inches long.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk