Find an equation of the line is the perpendicular to 30x-5y=5 and passes through the point (0,-3).

Step-by-step explanation:

Given line = 30x - 5y = 5 or y = 6x + 1

so, the slope of the given line is 6.

now, let the line which is perpendicular to the given line be y = mx + c

where,

m = slope of the line

c = constant

As we know, if two lines are perpendicular to each other, the value of product of there slopes are -1.

so, slope of given line × slope of perpendicular line = -1

⇒ 6(m) = -1

⇒ m =

By substitutiong the value of m in the equation, we get;

⇒

For c,

as the point (0,-3) passes through the line, we get;

⇒

⇒

Hence,

The line which is perpendicular to the given line and passes through (0,-3) is   .

bull

step-by-step explanation:

i think the length is 12 and the width is 17