The blue m& m was introduced in 1995. before then, the color mix in a bag of plain m& ms was (30% brown, 20% yellow, 20% red, 10% green, 10% orange, 10% tan). afterward it was (24% blue , 20% green, 16% orange, 14% yellow, 13% red, 13% brown). a friend of mine has two bags of m& ms, and he tells me that one is from 1994 and one from 1996. he won't tell me which is which, but he gives me one m& m from each bag. one is yellow and one is green. what is the probability that the yellow m& m came from the 1994 bag?

The probability that the yellow M&M came from the 1994 bag is 0.07407 or 7.407%

Step-by-step explanation:

Given

Before 1995

(Br) Brown = 30%

(Y) Yellow = 20%  =0.2

(R) Red = 20%

(G) Green =10%  =0.1

(O) Orange = 10%

(T) Tan = 10%

After 1995

(Br) Brown = 13%

(Y) Yellow = 14%  =0.14

(R) Red = 13%

(G) Green = 20% = 0.2

(O) Orange = 16%

(Bl) Blue = 24%

Since there are two bags, let A be the bag from 1994, and B be the bag from 1996

Then let AY imply we drew a yellow M&M from the 1994 bag

AG implies we drew a green M&M from the 1994 bag

BY implies imply we drew a yellow M&M from the 1996 bag

BG implies we drew a green M&M from the 1996 bag

P(AY) =0.2

P (BY) = 0.14

P(AG) =0.1

P(BG) =0.2

Since the draws from the 1994 and 1996 bag are independent,

therefore

The draws can happen in either of the 2 ways in (1) and (2) above

therefore total probability E is given as

E =

For the yellow one to be from 1994, it implies that the event to be chosen is

Since the total probability is given as E=0.054

then

Concluding statement: This is the condition for the Yellow one to come from 1994 and green from 1996 provided that they obey the condition from E

i recommend you do what your heart desires. if you're attracted to the same gender, then you're attracted to the same gender. you can't determine what your heart wants.

the answer for your question is

step-by-step explanation: