If you select a month at random from a leap year, what is the probability that the selected month will have an even number of days?

5/12

Step-by-step explanation:

First, list the months by the number of days each has:

Jan:  31, Feb:  28 or 29, Mar:  31, Apr:  30, May:  31, Jun:  30, Jul:  31, Aug:  31, Sep:  30, Oct:  31, Nov:  30, Dec:  31.

How many of these 12 months have an even number of days?

Feb, Apr, Jun, Sep, Nov (assuming that we ignore Leap Year):  5 months

Then the probability that the selected month will have an even number of days is

5 months

= 5/12

12 months

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: