Suppose an investment of $1,800 doubles in value every 7 years. how much is the investment worth after 42 years?
$151,200
$115,200
$21,600
$25,200

The investment worth after 42 years is $115200, so option 2 is correct

Solution:

Given, an investment of $1,800 doubles in value every 7 years. We have to find how much is the investment worth after 42 years from the given set of options.

Hence, the investment worth after 42 years is $115200, so option 2 is correct.

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

h/o/e/s mad

step-by-step explanation:

si si si