Assume a recent sociological report states that university students drink 4.10 alcoholic drinks per week on average, with a standard deviation of 1.9101. suppose jason, a policy manager at a local university, decides to take a random sample of 125 university students to survey them about their drinking habits. determine the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption. provide your answer with precision to two decimal places. mean of sampling distribution = standard deviation of sampling distribution =

The mean of the sampling distribution of the sample mean alcohol consumption is 4.10 alcoholic drinks per week on average.

The standard deviation of the sampling distribution of the sample mean alcohol consumption is 0.17.

Step-by-step explanation:

We have these following informations:

Assume a recent sociological report states that university students drink 4.10 alcoholic drinks per week on average, with a standard deviation of 1.9101.

Determine the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption.

The mean of the sampling distribution of the sample mean is the same of that university students. So the mean of the sampling distribution of the sample mean alcohol consumption is 4.10 alcoholic drinks per week on average.

The standard deviation of the sampling distribution of the sample mean alcohol consumption is the division of the standard deviation of the sample mean divided by the length of the sample. So

The standard deviation of the sampling distribution of the sample mean alcohol consumption is 0.17.

3=log(n)=2

answer a: product property

idk

step-by-step explanation:

idk