The path of his motorcycle was given approximately by h=-0.005x^2+2.39x+600 where h was measured in ft above the river and x was the distance from his launch ramp. how high above the river was the launch ramp? i found that the maximum height was 600ft and the horizontal distance was 234ft.

H = 600 ft.

ft at x =239 ft.

Step-by-step explanation:

The path of a motorcycle is given by .....(1) where H is the height above the river in ft and x is the distance from his launch camp.

Putting x = 0, the height of the launch camp from the river is H = 600 ft.

Now. differentiating equation (1), with respect to x both sides we get,

{Condition for H to be maximum is }

⇒ x = 239 ft.

So, ft. (Answer)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

3,000,540

step-by-step explanation: