P(x)=x^4-2x^3+kx-4 where k is an unknown integer
p(x)divided by (x-1) has a remainder of 0 what is the value of k?

k = 5.

Step-by-step explanation:

By the Factor Theorem if p(x) is divisible by x - 1 then p(1) = 0. So:

1^4 - 2*1^3 + k*1 - 4 = 0

1 - 2 + k - 4 = 0

k = 4 - 1 + 2

k = 5 (answer).

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.