Abatch of snack mix made of dried fruit and nuts contain 744g of nuts the ratio of nuts to dried fruit by weight is 12 to 13 how much does a batch of snack mix way?

In a bag of snack mix:

n = nuts       d = dried fruit

n = 744g        d = ???g

Ratio Nuts/Dried fruit = 12/13

This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits

If 744 is 12 parts then 744/12 is 1 part

744/12 = 62

1 part = 62g

there are 13 parts of dried fruit

13 x 62 = 806

744g of nuts + 806g of dreid fruit = 1550g

A batch of snack mix weigh 1550g, or 1.55kg

hope it helps :)

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

1. minimum

2. 6400

3. eight

hope this !