The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative startfraction 2 over 5 endfraction left-parenthesis x minus 10 right-parenthesis.. what is the standard form of the equation for this line?

2x – 5y = –15
2x – 5y = –17
2x + 5y = –15
2x + 5y = –17

For this case we have that by definition, the standard form of a linear equation is:

 We have the following equation of the point-slope form:

We manipulate the equation algebraically to convert it to the standard form:

We apply distributive property to the terms within parentheses, taking into account that:

We subtract 4 from both sides of the equation:

We multiply by 5 on both sides of the equation:

Adding 2x to both sides of the equation:

Subtracting 15 from both sides of the equation:

Thus, the standard form of the equation is:

Option C

you answer is a

step-by-step explanation:

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.