Find the slope of the line that is perpendicular to 3x+4y=20

4/3

Step-by-step explanation:

First, find the slope of the given equation.  To do this, solve it for 4y, and then for y:

Subtracting 3x from both sides, we get

4y = -3x + 20, and

dividing both sides by 4 yields

y = (-3/4)x + 5.  The slope of the given line is -3/4.

The slope of any line perpendicular to this one is the negative reciprocal of -3/4, meaning it would be +4/3.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

she drove 134 miles

step-by-step explanation: