4. three consecutive even integers are such that the sum of the smallest and 3 times the
second is 30 more than twice thee third. find the integers.

Integers are:

14, 16, 18

Step-by-step explanation:

Let three consecutive even integers be:

x          (smallest)

x + 2    (second)

x + 4    (third)

According to given conditions:

x + 3(x + 2) = 30+ 2(x + 4)

By simplifying:

x + 3x + 6 = 30 + 2x + 4

By adding like terms

4x + 6 = 34 + 2x

Now taking terms with x on left side and constants on right

4x - 2x = 34 - 6 (sign of transferred terms will be changed)

2x = 28

Dividing both sides with 2

x = 28/2

x = 14

So the consecutive integers will be:

x = 14

x + 2 = 14 + 2= 16

x + 4 = 14 + 4 = 18

I hope it will help you!