The sum of three consecutive integers is 21 larger
than twice the smallest integer. find the integers.

The consecutive integers are:

18, 19, 20

Step-by-step explanation:

Let the three consecutive integers be:

x

x+ 1

x+2

Now according to given conditions:

x + x+1 +x + 2 = 21 + 2x

Adding like terms:

3x + 3 = 21 + 2x

Taking terms with x on left side and constants on right side

3x - 2x = 21 - 3   (Sign of transferred terms will be changed)

x = 18

So the consecutive terms become:

x = 18

x + 1 = 19

x + 2= 20

I hope it will help you!

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