How many zeros are at the end of 458 · 885? explain how you can answer this question without actually computing the number. (hint: 10 = 2 · 5.) when this number is written in ordinary decimal form, each 0 at its end comes from a factor of , or one factor of 2 and one factor of . g

One zero

Step-by-step explanation:

To find : number of zeroes at the end of product 458 · 885 .

It's given that when this number is written in ordinary decimal form, each 0 at its end comes from a factor of , or one factor of 2 and one factor of . g

First, we will find factors of 458 and 885 .

From this factorisation, we get

i,e,

Here, we noticed that we have one 2 and one 5, which makes

So, we conclude that 458 · 885 ends at one zero .

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk