Choose the linear inequality that describes each graph.

y > – 5x + 3

y > – 5x – 3

y < – 5x + 3

y > – 3x + 5

Step-by-step explanation:

Starting from the y-intercept of you do by either moving five blocks north over one block west or five blocks south over one block east [west and south are negatives], then you shade everything to the right of the line because using the zero-interval test, also known as the test point [origin], we can determine what side of a line to shade. This is done by plugging "0" in for both y and x, then determining whether false or true will tell you which side to shade. In this case, we shade to the right of the line because when we plug the test point into the function, we get this false statement:

So, we do not want to shade the side with the origin. We would want to shade the OPPOSITE side, which is what you see in the graph.

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* In this case, do not worry about whether to use dashed or solid lines because since your inequality symbol is a greater than symbol, that already tells you that you need a dashed line, otherwise it would be solid if it were a greater than or equal to symbol [≥].

** Picking ANY point in the shaded region of a linear inequality equation will ALWAYS make an authentic statement.

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

a. -0.3 > -0.33