Car a and car b both depart the same location (point p) and drive on the same road in the same direction at the same speed. right now, car b is six times as many miles from point p as car a is. after both cars travel 45 more miles, car b will be three times as many miles from point p as car a.

which function shows the ratio of car a’s position to car b’s position after each vehicle travels x miles from point p?

a r(x)=30 + x45 + x

b r(x)=75 + x180 + x

c r(x)=30 + x180 + x

d r(x)=75 + x225 + x

Answer x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​x=\frac{4(7+y)}{5}x=​5​​4(7+y)​​

step-by-step explanation:

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60