Astore sells cans of paint for $8 each, and brushes for $12 each. if they sell 100 items, and
make $880, how many cans and brushes did they sell?
a

60 cans, 30 brushes
b

80 cans, 20 brushes
c

40 cans, 40 brushes
d

20 cans, 50 brushes

B.) 80 cans, 20 brushes

Step-by-step explanation:

Let the cans of paint be represented by variable p , and brushes by variable b

The first equation would be ; p + b = 100

p = 100 - b

The second equation would be;

8p + 12b = 880

Replace p in the equation by (100-b);

=8(100-b) + 12b =880

=800 - 8b +12b = 880

= subtract  800 from both sides to get;

4b = 880-800

4b = 80

divide both sides by 4 to solve for b;

b= 80/4

b = 20

If p + b = 100, then p+20 = 100

p = 100-20

p = 80

Therefore, they sold 80 cans of paint and 20 brushes

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐