An airport offers two shuttles that run different schedules. if both shuttles leave at 5: 00 p. m at what time will they next leave the airport together? shuttle a-every 6 minutes shuttle b-every 8 minutes

The answer is 5:48 p.m.

Step-by-step explanation:

First you have to find the Greatest Common Multiple(GCM) of the two. The reason for this is to find when they're the same again. In this case the GCM is 48 meaning that in 48 minutes they will leave the airport together.  Then you have to add that to the time they left together the first time, which was 5:00, adding 48 which is 5:48.

The answer would be 5:48 p.m. Probably not but brainliest please? ^^

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.