Solve the rational equation 4 divided by x equals quantity 3 times x plus 2 end quantity divided by x squared, and check for extraneous solutions.

x = 0; x = 2 is an extraneous solution

x = 2; x = 0 is an extraneous solution

x = 0; x = −2 is an extraneous solution

x = −2; x = 0 is an extraneous solution

Option 1- x = 0; x = 2 is an extraneous solution

Step-by-step explanation:

Given : The rational equation

To find : Solve the equation and check for extraneous solutions ?

Solution :

The equation

Cross multiply,

For extraneous solution put the value of x in the equation,

At x=0,

True

At x=2,

True

So, At x=0,2 is an extraneous solution

Therefore, Option 1 is correct.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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