Jill needs wrapping paper for a cylindrical gift that is 10 inches high and measures 4 inches across the base. how much wrapping paper will she need

formula: sa = 2πr² + ²πrh (use 3.14 for π)

  150.72 in²

Step-by-step explanation:

The radius of the cylinder is half its diameter, so is 2 inches. We can rearrange the formula to make it easier to use, then fill in the numbers and do the arithmetic.

  SA = 2πR(R +H) = 2(3.14)(2)(2+10) = 150.72 . . . . square inches

Jill will need 150.72 square inches of wrapping paper.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.