Find the coordinates of the image’s vertices.

a triangle with vertices l(–1, 5), m(–1, 7), and n(–8, 5) is rotated 270 counterclockwise about the origin.

a. l’(–5, 1), m’(–7, 1), and n’(–5, 8)
b. l’(1, 5), m’(1, 7), and n’(8, 5)
c. l’(5, 1), m’(7, 1), and n’(5, 8)
d. l’(5, –1), m’(7, –1), and n’(5, –8)

C. L' (5,1), M'(7,1) and N'(5,8)

Explanation:

For the rotation of a point 270° counterclockwise about the origin, the following rule applies:

(x , y) > (y , -x)

This means that, to get the image point:

1- We swap the values of the x and y coordinates in the original point

2- We change the sign of the x-coordinate of the original point (which is the y-coordinate in the image)

Now, for the givens, we simply apply the above rule to get the image:

L is (-1 , 5) > L' is (5 , 1)

M is (-1 , 7) > M' is (7 , 1)

N is (-8 , 5) > N' is (5 , 8)

Hope this helps :)

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8