Write an equation for the line that is parallel to the given line and passes through the given point
y= 2x + 4; (3,8)

y = 2x + 2

Step-by-step explanation:

The equation ofa line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 4 ← is in slope- intercept form

with m = 2

Parallel lines have equal slopes , thus

y = 2x + c ← is the partial equation

To find c substitute (3, 8) into the partial equation

8 = 6 + c ⇒ c = 8 - 6 = 2

y = 2x + 2 ← equation of parallel line

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345