In an intro stats class, 57% percent of students eat breakfast in the morning and 80% of students floss their teeth. forty-six percent of students eat breakfast and also floss their teeth.
3. what is the probability that a student from this class eats break feast but does not floss their teeth?
a. 57%
b. 11%
c. 34%
d. 9%
e. 91%

B. 11%

Step-by-step explanation:

Let A = Event that students eat breakfast in the morning.

B= Event that students floss their teeth.

We are given P(A)=57%=0.57

P(B)=80%=0.80

P(A∩B) = 46% =0.46

Now, the probability that a student from this class eats break feast but does not floss their teeth :-

Hence, the probability that a student from this class eats break feast but does not floss their teeth= 11%

1010: 3030

is it i think

table 3 represents a direct variation function. : )