What function describes a line with slope 4/3 and passing through the point (2,5) ?

The answer is: f(x) = 4/3x + 7/3

Step-by-step explanation:

Start with the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 4/3(x - 2)

y - 5 = 4/3x - 8/3

y = 4/3x - 8/3 + 5

y = 4/3x - 8/3 + 15/3

y = 4/3x + 7/3

Replace y with f(x):

f(x) = 4/3x + 7/3

proof:

f(2) = 4/3 * 2 + 7/3

= 8/3 + 7/3 = 15/3 = 5

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: