Aball is thrown upward and outward from a height of 8 feet. the height of the ball, f(x), in feet, can be modeled by 1(x) -0.1x2+14x+8 where x is the ball's horizontal distance, in feet, from where it was thrown use this model to solve parts (a) through (c). a. what is the maximum height of the ball and how far from where it was thrown does this occur? feet from the point of release. feet, which occurs the maximum height is (round to the nearest tenth as needed)

Step-by-step explanation:

A graphing calculator can show the answers to these questions.

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For quadratic ax²+bx+c, the x-value of the vertex is ...

  x = -b/(2a)

For the given expression, the vertex is ...

  x = -14/(2(-0.1)) = 70

The distance from the point of release to the point of maximum height is 70 feet.

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The height of the ball at that point is ...

  f(70) = (-0.1·70 +14)70 +8 = 7·70 +8 = 498 . . . . feet

The maximum height is 498 feet.

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the answer is $42.96

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