The distribution of certain test scores is a nonstandard normal distribution with a mean of 50 and a standard deviation of 6. what are the values of the mean and standard deviation after all test scores have been standardized by converting them to z scores using z = (x - μ) / σ?

0 and 1

Step-by-step explanation:

Given that,

The distribution of certain test score is non- standard normal distribution with mean 50 and  a standard deviation of 6.

we know that the

standard normal deviation has mean 0 and standard deviation 1.

So, All test scores have been standardized by converting them to z score.

mean = 0 and standard deviation= 1

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3