Using the distance formula, classify the following triangle. a(7, -2) b(-4, 9) c(-3,-1)

A(7, -2) B(-4, 9) C(-3,-1)

AB² = (7 - -4)² + (9 - -2)² = 121 + 121 = 242

AC² = (7 - -3)² + (-2 - -1)² = 100 + 1 = 101

BC² = (-3 - -4)² + (9 - -1)² = 1 + 100 = 101

Since AC² + BC² ≠ AB² this isn't a right triangle

It is clearly an isosceles triangle because AC² = BC²

Isosceles

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

the answer is d. (1.2, -4.7) on edgn

hope this !