a boy scout troop is selling christmas trees at a local tree lot. in the morning, they sold 20 douglas fir trees and 23 noble fir trees, earning a total of $2,417. in the afternoon, they sold 20 douglas fir trees and 18 noble fir trees, earning a total of $2,022. how much does each type of tree cost?

The cost of 1 Douglas Fir Tree = $30

The cost of 1 Noble Fir Tree = $ 79

Step-by-step explanation:

Let the cost of 1 Douglas Fir tree =  $ x

Let the cost of 1 Noble Fir tree = $ y

Total Amount Earned in morning = $2,417

Total Amount Earned in evening = $2,022

Now, according to the question:

20 x + 23 y = 2417

and 20 x + 18 y = 2022

Subtraction both equation , we get

20 x + 23 y  - (20 x + 23 y)  = 2417 - 2022

or,  20x - 20x + 23 y - 18 y  = 395

or, 5 y = 395

⇒ y = 395 / 5 =  79

Hence, the cost of 1 Noble Fir Tree = $ 79

Now, put the value of y in 20 x + 23 y = 2417 , we get

20x + 23(79) = 2417

or, 20x = 2417 - 1817 = 600

or, x  = 600/20  = 30

Hence, the cost of 1 Douglas Fir Tree = $30

answer is 67%

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b