Given the equation square root of quantity 3x plus 4 end quantity equals 5, solve for x and identify if it is an extraneous solution.

7; solution is not extraneous

7; solution is extraneous

four thirds; solution is not extraneous

four thirds; solution is extraneous

7; solution is not extraneous

Step-by-step explanation:

we have

Solve for x

squared both sides

subtract 4 both sides

Divide by 3 both sides

Verify

Substitute the value of x in the original equation

----> is true

therefore

The value of x=7 is a solution, Is not a extraneous

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

da freeck kinda math is this just drop out

step-by-step explanation: