The given line passes through the points (0, -3) and (2, 3).
what is the equation, in point-slope form of the line that is
parallel to the given line and passes through the point
(-1, -1)?
y+1 = - 3(x + 1)
+1 = -(x + 1)
v+1 = $(x + 1)
5
-3 -2 1
/1
3
4
y + 1 = 3(x + 1)
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The equation, in point-slope form of the line that is  parallel to the given line and passes through the point  (-1, -1) is y + 1 = 3(x + 1).

Solution:

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and  passes through (-1, -1).

Now, let us find the slope of the given line.

So, slope of given line is 3,  

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

Hence, the line equation is y + 1 = 3(x + 1).

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )