There is an animal farm where chickens and cows live. all together, there are 84 heads and 210 legs. how many chickens and cows are there on the farm?

1 Chicken have = 2 legs

1 Cow have = 4 legs

No of cows = x

No of chickens = y

Total no of legs = 4x + 2y = 210(1)

Total No of heads = x + y = 84(2)

x = 84 - y( from (2) )

Substituting the above equation in (1)

4 ( 84 - y) + 2y = 210

336 - 4y + 2y = 210

336 - 2y = 210

-2y = -126

= y = 63

No of cows = 84-63 = 21

∴ Total no of cows = 21

Total no of chickens = 63

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

i do not know this sorry : (