Use deductive reasoning to show that the following procedure always produces the number 6. procedure: pick a number. add 4 to the number and multiply the sum by 3. subtract 6 and then decrease this difference by the triple of the original number.

procedure always produces 6

Step-by-step explanation:

Let 'n' be the unknown number

Add 4 to the number : n+4

multiply the sum by 3.

multiply the sum n+4 by 3

Now subtract 6, so we subtract 6 from 3n+12

finally decrease the difference by the tripe of the original number

triple of original number is 3n

so the procedure always produces 6

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step-by-step explanation:

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