The steps below describe the construction of a line ag which is parallel to segment pq and passes through a point a outside of pq: step 1 shows a segment pq with an external point a. a line drawn from a intersects pq at a point b. step 2 shows an arc drawn from b that intersects bq in d and ba in e. step 3 shows an arc drawn from point a that intersects the segment ba extended in a point f which statement describes the next step?

d

step-by-step explanation:

d

to have more of what you want like money

step-by-step explanation:

save it by not spending on unnecessary stuff and have more

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen