If x is a geometric random variable, show analytically that p(x = n+k|x > n) = p(x = k) .give a verbal argument using the interpretation of a geometricrandom variable as to why the preceding equation is true. a geometric random variable is a discrete random variable with aprobability mass function defined as follows: p(n)=(1-p)n-1p, n=1, 0 < p < 1.

P[(X=n+k)] ∩ X>n)] =P[X=K]

Step-by-step explanation:

If X is a geometric random variable then

for success probability = p

so for failure q= 1-p

Now as given

Now for the P parameter we have

x∈{1,2,3,....∞}

P[(X=n+k)] ∩ X>n)] = P(X=n+K)

P[(X=n+k)] ∩ X>n)] =

P[(X=n+k)] ∩ X>n)] =

P[(X=n+k)] ∩ X>n)] =P[X=K]

is there a picture

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10