Arectangular garden is 5ft long, 3ft wife. a second rectangular garden has dimensions that are doubled the dimensions of the first garden. what is the percent of change in perimeter from the first garden to the second garden? the percent increase ? % from the first garden to the second garden?

100%

Step-by-step explanation:

Perimeter of first garden is given by 2(l+w) where l is length and w is width

Perimeter=2(5+3)=16

The dimensions of second rectangle is doubled hence 10 ft by 6 ft

Perimeter=2(10+6)=32

Change in area will be 32-16=16

Percentage change in area is 16/16*100=100%

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.