Objects a and b are in harmonic motion modeled by
ya = 8 sin(2t − π/3) and yb = 8 sin(2t − π/4)

the phase difference between ya and yb is

The phase difference between yA and yB is  

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - )         And

yB = 8 sin(2t  - )

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -   + )

Or, phase difference between yA   and  yB =

I.e phase difference between yA   and  yB =

Hence The phase difference between yA and yB is   Answer

  -π/12

Step-by-step explanation:

yA has a phase shift of -π/3; yB has a phase shift of -π/4. The difference between their phases is ...

  -π/3 -(-π/4) = (-4/12 +3/12)π = -π/12

yA lags yB by π/12 radians.

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step-by-step explanation:

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step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.