Aball was thrown upward and its height is modeled by the function h(t) = -4.9t^2 + 58.8t + 98, where h is the height of the ball in meter and t is the time in seconds that the ball is in the air. find the maximum height of the ball to the nearest meter.

274 meters

Step-by-step explanation:

The function is a downward parabola.  So the highest point is at the vertex.

t = -b / (2a)

t = -(58.8) / (2 × -4.9)

t = 6

Evaluate the function at that point:

h(6) = -4.9 (6)² + 58.8 (6) + 98

h(6) = 274.4

Rounded to the nearest meter, the maximum height reached is 274 meters.

i just took the test, the correct answer is .. 31.5 in.