If f varies jointly as q^2 and h, and f=96 when q=4 and h=3, find q when f=48 and h=6.

If f varies jointly as q^2 and h, and f=96 when q=4 and h=3 then the value of q when f = 48 and h = 6 is 2

Solution:

Given that, f varies jointly as q^2 and h

And f=96 when q=4 and h=3

Now substitute f, q, h values in above formula  

We have to find q when f=48 and h=6

Hence, the value of q is 2

answer: sine

step-by-step explanation: