Motors inc. manufactured 356 cars with automatic transmissions, 240 with power steering, and 96 with both of these options. how many cars were manufactured with at least one of the two options?

The answer is 692.

Step-by-step explanation:

Number of cars with automatic transmissions = 356

Number of cars with power steering = 240

Number of cars with both of these options = 96

Number of cars that were manufactured with at least one of the two options = x

x = Number of cars with automatic transmission + Number of card with power steering + Number of cars with both of these options

x = 356 + 240 + 96

x = 692

The number of cars manufactured with at least one of the two options is 692.

The Number of cars were manufactured with at least one of the two options is 509

Explanation:

Let A = no. of cars manufactured with automatic transmissions = 356

and that with power steering = B = 240 which is given

And those with both these options is given by A∩B

which is A intersection B is = 96 given

We know that AUB =  which gives the no. of cars manufactured with at least one of the two options  and is given by

AUB = A + B - A∩B

Substituting values in above we get

AUB = 356 +240 - 96 = 509 which is the  Number of cars were manufactured   with at least one of the two options

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: