Acommercial jet can fly 868 miles in 2 hours with a tailwind but only 792 miles in 2 hours into a headwind. find the speed of the jet in still air and the speed of the wind.

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

x -----> the speed of the wind in miles per hour

y ----> the speed of the jet in still air in miles per hour

we know that

With a tailwind

----> equation A

With a headwind

----> equation B

solve the system of equations A and B by elimination

Adds equation A and equation B

Find the value of x

therefore

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

lol

step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option