What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?

The nth term of the series is

Step-by-step explanation:

Given: Third term = 24 and r = 6

We are given third term and common ratio of geometric series.

Formula:

For third term, n=3 and r=6

We need to find nth term of the series

Hence, The nth term of the series is

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Step-by-step explanation:

2/3 * 6^(n-1)

Step-by-step explanation:

The formula is a*r^(n-1)

so if the 3rd term (n=3) is 24 and the common ratio, r, is 6

24 = a* 6^(3-1)

So we are looking for a, yeah. 3-1 is 2 so 6^2 is 36. Simplify

24/36 = a

2/3 = a

Then just use that to write formula of the sequence

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!