Everybody's blood pressure varies over the course of the day. in a certain individual the resting diastolic blood pressure at time t is given by b(t) = 90 + 3 sin(πt/12), where t is measured in hours since midnight and b(t) in mmhg (millimeters of mercury). find this person's diastolic blood pressure at the following times. (round your answers to one decimal place.) (a) 6: 00 a. m. mmhg (b) noon mmhg (c) 6: 00 p. m. mmhg

9514 1404 393

  (a) 6 am: 93

  (b) noon: 90

  (c) 6 pm: 87

Step-by-step explanation:

(a) The given time is 6 hours after midnight, so the BP is ...

  B(6) = 90 +3sin(π·6/12) = 90 +3 = 93 . . . mmHg

__

(b) The given time is 12 hours after midnight, so the BP is ...

  B(12) = 90 +3sin(π·12/12) = 90 +0 = 90 . . . mmHg

__

(c) The given time is 18 hours after midnight, so the BP is ...

  B(18) = 90 +3sin(π·18/12) = 90 -3 = 87 . . . mmHg

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

idk

step-by-step explanation: