The proof shows that abcd is a rectangle. which of the following is the missing reason?

a. angle-side-angle postulate
b. side-angle-side postulate
c. angle-angle-side postulate
d. side-side-side postulate

Side-side-side postulate

Step-by-step explanation:

In the first statement, we are given that AC = BD (1){It is given}

Now, in the second statement, we are given that AB = DC (2){ Because the parallelogram has equal opposite sides}

Now, again we are given that AD = DA (3) {From the symmetric property}

Now, conditions (1), (2), and (3) are applicable to say that Δ ABD and Δ ACD are congruent.

Since there are three sides involved to say Δ ABD ≅ Δ ACD, so it is by Side-side-side postulate. (Answer)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: