1. draw the side view of your roller coaster on graph paper. for the sake of simplicity, assume that your roller coaster track never turns left or right.
o in order to gain speed, the roller coaster should have an initial climb, at least two hills, and one loop.
2. label the x- and y-axes. the value of x measures the horizontal distance from the roller coaster cart to the starting point, and the value of y represents the height of the roller coaster cart.
3. plot ordered pairs on the initial climb and determine the slope.
4. what is the equation of the line that represents your initial climb?
5. what is the domain and range of your roller coaster?
6. plot ordered pairs at the top and the end of each hill. find the rate of change
to determine which hill is steeper? how do you know

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

lol.

it's ok we all do this sometimes.

-aparri

using pemdas, (order of operations) you'll see the answer is 24.