what is the area of trapezoid abcd? a(-2,2) b(2,5) c(11,-7) d(1,-2)

50 sq. units

Step-by-step explanation:

Join one diagonal of the trapezoid ABCD.

Assume that AC is the diagonal.

So, Area of the trapezoid = Area of Δ ABC + Area of Δ CAD.  

Now, coordinates of A(-2,2), B(2,5), C(11,-7) and D(1,-2) are given.

We know, that three vertices of a triangle are , and respectively, then the area of the triangle will be given by  

Hence, area of Δ ABC will be  

sq units.

Again, area of Δ CAD will be  

sq units.

Therefore, the area of the trapezoid ABCD will be (37.5 + 12.5) = 50 sq, units. (Answer)

here the number -5 is all of the following except a rational number.

step-by-step explanation:

step-by-step explanation: