Find the derivative of the function f(x) = 6x^-3 + x^2 + 14.

If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then

Since opening night, attendance at play a has increased steadily, while attendance at play b first rose and then fell. equations modeling the daily attendance y at each play are shown below, where x is the number of days since opening night. on what day(s) was the attendance the same at both plays? what was the attendance? play a: y = 8x + 191 play b: y = -x^2 + 26x + 126

Simplify the expression. -2/5(10+15m-20n)